A,B
and C are three non-collinear points. The figure which surronded by
segments of the lines AB, BC and CA is called triangle having A,B and C
as its vertices. All the points situated on AB, BC and CA are included
in this triangle. In a triangle, an exterior angle is greater than
either of the interior opposite anglesThe sum of all the angles in any
triangle is 180º.
There are types of triangle
- Equilateral triangles,
- Isosceles triangles
- Scalene triangles
- Right Triangles
Understanding The Formula for Distance is always challenging for me but thanks to all math help websites to help me out.
Types of Triangles:
Right Triangles:
In a right triangle is a triangle with a 90° right angle triangle
Equilateral Triangles
In equilateral triangle all three sides are in equal length also three angles are equal and they are 60º in each.
Isosceles Triangles
In isosceles triangle, two sides are in equal length. The angles opposite are also equal sides
Scalene Triangles
A scalene triangle has no equl sides of its length. Its angles are also all different in measure.
Finding distance Of a Triangle:
Example 1:
Find the distance of triangle whose points are (-2, -3), (-4, 4), (5,8)
Solution:
to find distance of triangle where (x1,y1)=(-2,-3)
(x2,y2)=(-4,4)
sqrt((x2-x1)^2 +(y2-y1)^2)`
=`sqrt(((-4-(-2))^2+4-(-3)^2))`
=`sqrt((-4+2)^2+(4+3)^2)`
=`sqrt((-2)^2+7^2)`
=`sqrt(4+49)`
length of one side =7.28
similarly we can find another sides
Example 2:
Find the distance of triangle whose points are (2, 3), (4, 6),(5,0)
Solution:
to find distance of triangle where (x1,y1)=(2,3)
(x2,y2)=(4,6)
sqrt((x2-x1)^2 +(y2-y1)^2)`
=`sqrt((4-2)^2+(6-3)^2))`
=`sqrt((2)^2+3^2)`
=`sqrt(4+
length of one side =`sqrt(13)`
similarly we can find another side lengths
My forthcoming post is on 10th samacheer books will give you more understanding about Algebra
=`sqrt((2)^2+3^2)`
=`sqrt(4+
length of one side =`sqrt(13)`
similarly we can find another side lengths
My forthcoming post is on 10th samacheer books will give you more understanding about Algebra
Example 3:
Find the distance of triangle whose points are (1, -3), (2, 5),(4,6)
Solution:
to find distance of triangle where (x1,y1)=(1,-3)
(x2,y2)=(2,5)
`sqrt((x2-x1)^2 +(y2-y1)^2)`
=`sqrt((2-1)^2+(5-(-4))^2))`
=`sqrt((1)^2+9^2)`
=`sqrt(1+81)`
=`sqrt(82)`
Similarly we can find another two side lengths.
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