Radical symbol used to indicate the square root or nth root.
Radical of an algebraic group, a concept in algebraic group theory.
Radical of a ring, in ring theory, a branch of mathematics, a radical of
a ring is an ideal of "bad" elements of the ring. Radical of a module,
in the theory of modules, the radical of a module is a component in the
theory of structure and classification. Radical of an ideal, an
important concept in abstract algebra. The radical symbol is ' √ ' . The
cubic root of x can be expressed as `root(3)(x)`
Understanding Addition Practice is always challenging for me but thanks to all math help websites to help me out.
Source Wikipedia.
Multiplication property rule `root(n)(x)` *`root(n)(y)` = `root(n)(x*y)`
Division property rule `sqrt(x/y)` = `sqrt x /sqrt y`
General Relation between exponential and radical expression `root(n)(x)`m =( `root(n)(x)` )m = (x1/n )m = xm/n
√ -1 ×√-1 = -1 where as `sqrt((-1) * (-1)) ` = 1
Solution:
` (sqrt(16a^4)) (sqrt((-25)a^3))` = ` (sqrt(16a^4)) (sqrt((-25)a^3))`
= (4a2 a `sqrt(-25a)` )
= 4a3 `sqrt((-1)25a)` we know, √(-1) = i
= i 4a3 `sqrt(25a)`
= i 4a3 (5) `sqrt(a)`
= i 20a3 `sqrt(a)`
Answer: i 20a3 `sqrt(a)`
Math radicals practice problem 2:
Simplify the radicals: `sqrt((8x^2)/(y^5z^7)) `
Solution:
Step 1: Multiply and divide by yz
` sqrt((8x^2)/(y^5z^7))` = `sqrt((8x^2 * yz) / (y^5z^7 *yz))`
Step 2: Multiply the variable with exponent
= `sqrt((8x^2yz) / (y^6z^8))`
Step 3: Square root of x2y6z8 = xy3z4
Square root of 8 = 2`sqrt2 `
So the answer = ` ((2x) / (y^3z^4)) sqrt(2yz)`
Answer: ` ((2x) / (y^3z^4)) sqrt(2yz)`
Math radicals practice problem 3:
Simplify the radicals : `sqrt(64)/sqrt49 + sqrt169 `
Solution:
Step 1: Very smallest factors of 64 = 8 × 8
`sqrt(64)` = `sqrt(8 * 8) ` = 8
Step 2: Very smallest factors of 169 = 13 × 13
`sqrt(169)` = `sqrt(13 * 13)`
Step 3: Take square root of 169 = 13
Step 4: Very smallest factors of 49 = 7 × 7
`sqrt(49)` = `sqrt(7 * 7)`
Step 5: Take square root of 49= 7
Step 6: so, `sqrt(64) /sqrt(49)` = `8 / 7 `
Step 7: Now , `sqrt(64)/sqrt49 + sqrt169 ` = `8 / 7 `+ 13 = `(8 + 91)/7`
Step 8: Simplification of `sqrt(64)/sqrt49 + sqrt169 ` = ` 99/7 `
Answer: ` 99/7 `
Math radicals practice problem 4:
Simplify the radicals: `(sqrt36) (3sqrt(45a^2))`
Solution:
`(sqrt36) (3sqrt(45a^2))` = (`sqrt(6 xx 6)` ) (`3sqrt(45a^2)` )
= `(6) ( 3a sqrt(9 * 5))`
= (6) (3a(`3sqrt5` ))
= 6 (9a) `sqrt5`
= 54a `sqrt5`
Answer: 54a `sqrt5`
I am planning to write more post on cbse syllabus english. Keep checking my blog.
Math radicals practice problem 5:
Find the cubic root of 135
Solution:
The very smallest factor of 135 = 3 * 3 * 3 * 5
Cubic root of 135 `root(3)(135)` = `root(3)(3 * 3 * 3 * 5)`
= `3 ` `root(3)(5)`
Answer: `3 ` `root(3)(5)`
Understanding Addition Practice is always challenging for me but thanks to all math help websites to help me out.
Source Wikipedia.
Basic identities and properties of radical:
Multiplication property rule `root(n)(x)` *`root(n)(y)` = `root(n)(x*y)`
Division property rule `sqrt(x/y)` = `sqrt x /sqrt y`
General Relation between exponential and radical expression `root(n)(x)`m =( `root(n)(x)` )m = (x1/n )m = xm/n
√ -1 ×√-1 = -1 where as `sqrt((-1) * (-1)) ` = 1
Math radicals practice problems:
Math radicals practice problem 1:
Simplify the radical expression:` (sqrt(16a^4)) (sqrt((-25)a^3))`Solution:
` (sqrt(16a^4)) (sqrt((-25)a^3))` = ` (sqrt(16a^4)) (sqrt((-25)a^3))`
= (4a2 a `sqrt(-25a)` )
= 4a3 `sqrt((-1)25a)` we know, √(-1) = i
= i 4a3 `sqrt(25a)`
= i 4a3 (5) `sqrt(a)`
= i 20a3 `sqrt(a)`
Answer: i 20a3 `sqrt(a)`
Math radicals practice problem 2:
Simplify the radicals: `sqrt((8x^2)/(y^5z^7)) `
Solution:
Step 1: Multiply and divide by yz
` sqrt((8x^2)/(y^5z^7))` = `sqrt((8x^2 * yz) / (y^5z^7 *yz))`
Step 2: Multiply the variable with exponent
= `sqrt((8x^2yz) / (y^6z^8))`
Step 3: Square root of x2y6z8 = xy3z4
Square root of 8 = 2`sqrt2 `
So the answer = ` ((2x) / (y^3z^4)) sqrt(2yz)`
Answer: ` ((2x) / (y^3z^4)) sqrt(2yz)`
Math radicals practice problem 3:
Simplify the radicals : `sqrt(64)/sqrt49 + sqrt169 `
Solution:
Step 1: Very smallest factors of 64 = 8 × 8
`sqrt(64)` = `sqrt(8 * 8) ` = 8
Step 2: Very smallest factors of 169 = 13 × 13
`sqrt(169)` = `sqrt(13 * 13)`
Step 3: Take square root of 169 = 13
Step 4: Very smallest factors of 49 = 7 × 7
`sqrt(49)` = `sqrt(7 * 7)`
Step 5: Take square root of 49= 7
Step 6: so, `sqrt(64) /sqrt(49)` = `8 / 7 `
Step 7: Now , `sqrt(64)/sqrt49 + sqrt169 ` = `8 / 7 `+ 13 = `(8 + 91)/7`
Step 8: Simplification of `sqrt(64)/sqrt49 + sqrt169 ` = ` 99/7 `
Answer: ` 99/7 `
Math radicals practice problem 4:
Simplify the radicals: `(sqrt36) (3sqrt(45a^2))`
Solution:
`(sqrt36) (3sqrt(45a^2))` = (`sqrt(6 xx 6)` ) (`3sqrt(45a^2)` )
= `(6) ( 3a sqrt(9 * 5))`
= (6) (3a(`3sqrt5` ))
= 6 (9a) `sqrt5`
= 54a `sqrt5`
Answer: 54a `sqrt5`
I am planning to write more post on cbse syllabus english. Keep checking my blog.
Math radicals practice problem 5:
Find the cubic root of 135
Solution:
The very smallest factor of 135 = 3 * 3 * 3 * 5
Cubic root of 135 `root(3)(135)` = `root(3)(3 * 3 * 3 * 5)`
= `3 ` `root(3)(5)`
Answer: `3 ` `root(3)(5)`
No comments:
Post a Comment