Parabola
is one of the conic sections whose eccentricity is equal to 1.
Eccentricity of an conic section is defined as the how it is deviating
from circular shape .The parabola has three major components.this
article will help you to find vertex of parabola as a calculator.
i)Vertex
ii)Focus
iii) Directrix
iv)Axis
Ex:1
Given the equation of parabola Y2 = 16X find the focus of parabola
solution:
Comparing with standard form of equation
Y2 = 4aX
we get vertex of parabola as
(0,0)
EX 2:FInd vertex of parabola
Y2 + 2y +1 = 3x-9
solution:-
transforming into standard equation
=> (y+1)2 =3(x-3)
on comparing with (Y-k)2 =4a(X-h)
vertex (h,k)=(3,-1)
My forthcoming post is on sine taylor series, model question paper for 10th samacheer kalvi will give you more understanding about Algebra
Ex 3: Find vetex of parabola
X2-2x+4 = 2Y-1
solution:
Converting to standard form (X-h)2 =4a(Y-k)
X2-2x+4 = 2Y+1
=> (X-2)2 = 2(Y+1/2)
=> (h,k)= (2 , -1/2).
i)Vertex
ii)Focus
iii) Directrix
iv)Axis
Expalnation to find vertex of parabola calculator
Definition of parabola :
Parabola
is the locus of points whose distance from fixed line, called as
directrix, and a from a fixed point , called as focus,is equal.
Vertex of parabola :-
The vertex of parabola is the point where the parabola changes its direction.It is apoint where the parabola crosses its axis.
Features of vertex of a parabola :-
i)It lies on the parabola
ii)It lies on axis of parabola.
iii)It is apoint equidistant from focus and directrix of parabola.
Standard forms of a parabola :-
parabolas having vertex at (0,0)
i)Y2 = 4aX
ii)Y2 = -4aX
iii)X2 = 4aY
iv)X2 = -4aY
Parabolas having vertex at (h,k)
i)(Y-k)2 = 4a(X-h)
ii)(Y-k)2 = -4a(X-h)
iii)(X-k)2 = -4a(Y-h)
iv)(X-k)2 = 4a(Y-h)
Calculation of vertex of parabola :-
i) parabola is to be transformed into one of the standard forms given above to find the vertex of parabola.
examples to find vertex of parabola calculator
Ex:1
Given the equation of parabola Y2 = 16X find the focus of parabola
solution:
Comparing with standard form of equation
Y2 = 4aX
we get vertex of parabola as
(0,0)
EX 2:FInd vertex of parabola
Y2 + 2y +1 = 3x-9
solution:-
transforming into standard equation
=> (y+1)2 =3(x-3)
on comparing with (Y-k)2 =4a(X-h)
vertex (h,k)=(3,-1)
My forthcoming post is on sine taylor series, model question paper for 10th samacheer kalvi will give you more understanding about Algebra
Ex 3: Find vetex of parabola
X2-2x+4 = 2Y-1
solution:
Converting to standard form (X-h)2 =4a(Y-k)
X2-2x+4 = 2Y+1
=> (X-2)2 = 2(Y+1/2)
=> (h,k)= (2 , -1/2).
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